PHAS2441 Session 7: Second-order Runge Kutta method. February 2, 2015 We’re starting from Euler’s method for solving differential equations of the form dx = f(x,t) (1) to obtain x(t). Given starting condition for some t, Euler’s method uses a Taylor expansion to solve the equation at a later time t + h: x(t + h) […]
PHAS2441 Session 7 Second order Runge Kutta method Read More »
comp273 template match displayBuffer: .space 0x40000 # space for 512×256 bitmap display errorBuffer: .space 0x40000 # space to store match function templateBuffer: .space 0x100 # space for 8×8 template imageFileName: .asciiz “pxlcon512x256cropgs.raw” templateFileName: .asciiz “template8x8gs.raw” # struct bufferInfo { int *buffer, int width, int height, char* filename } imageBufferInfo: .word displayBuffer 512 128 imageFileName errorBufferInfo:
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BBAE16502 Exercise (E3) Due date: March 27, 2023 23:59 Human behavior plays significant role in emergency situations of evacuations. By conducting simulations, researchers can explore how different elements impact the evacuation process and assess the effectiveness and efficiency of different evacuation approaches and plans. In this exercise, you should: ➢ Import the image file “room.png”
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Connect 4 – 2023 Assignment Project Exam Help In this assignment, you are going to design and to develop a 2-player connection board game, in which Home the players first choose a color called token and then take turns dropping the colored token into columns, and the first player who connects four tokens of same
RUN 15% 20% 0% IF PROGRAM DOESN’T RUN MAX. 70% REFER TO SCOPE Read More »
######################################################################## # COMP1521 23T1 — Assignment 1 — Othello! # !!! IMPORTANT !!! # Before starting work on the assignment, make sure you set your tab-width to 8! # It is also suggested to indent with tabs only. # Instructions to configure your text editor can be found here: # https://cgi.cse.unsw.edu.au/~cs1521/22T1/resources/mips-editors.html # !!! IMPORTANT !!!
Sigma-Delta Data Converters Laboratory Session 3 1.0 Objectives This laboratory comprises 2 sets of exercises. In the first set of exercises, we will study the properties of third order modulator topologies. Modulators with noise-shaping order > 2 can be unstable for some or even all possible inputs, usually displaying chaotic limit cycle behaviour unrelated to
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Design an audio band ADC with the following specifications over 20 Hz – 20 kHz: [1] Maximum stable input amplitude (MSA) at least +/-0.85 for a full-scale input range of +/-1.0. [2] Signal to quantisation noise ratio at MSA at least 105 dB. [3] Total (audio band only) harmonic distortion at input level 1 dB
Human behavior plays significant role in emergency situations of evacuations. By conducting simulations, researchers can explore how different elements impact the evacuation process and assess the effectiveness and efficiency of different evacuation approaches and plans. In this exercise, you should: ➢ Import the image file “room.png” into your NetLogo environment. ➢ There are 200 guests
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Assignment THREE: DATA ART PROJECT Opens: Saturday, 1 April 2023, 12:00 AM Due: Friday, 7 April 2023, 11:59 PM Data Art: Map a System that has never been Depicted Before. “Beauty” (1993) : Olafur Elaisson Using any appropriate means, students must create an artwork based on a complex dataset. The artwork can take any form
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计算机组织 家庭作业(第二次截止) 关于处理和提交的说明 订阅DeepL Pro以翻译大型文件。 欲了解更多信息，请访问www.DeepL.com/pro。 作业的解决方案必须是独立创建的。如果提交的材料与其他材料相同或惊人的相似，将被评估为抄袭抄袭 是一种欺骗行为，会导致整个模块考试的成绩为 “不及格”。 • 请使用MARS来模拟你的解决方案。请确保你提交的方案能在MARS中执行。 • 你将收到每个任务的单独文件，包括默认和解决方案部分。请在所提供的空间中加入你的姓名 和预科生编号。要解决该任务，只需在标记下面的解决方案部分工作。 #+ 解决方案部分 #+ • 你的解决方案也必须能在给定值之外的其他输入值下工作。为了用其他输入值测试你的代码， 你可以改变解决方案部分的样本数据。 • 请不要对默认部分做任何修改，保留默认标记(以#+开头的行)不做任何修改。 • 一个正确的解决方案必须符合已知的注册惯例。通常情况下，尽管 如果不遵守登记簿的惯例，就会产生正确的结果。在这种情况下，仍然会被扣分。 • 如果你想在你的解决方案中为数据使用额外的内存区域，请只使用堆栈，而不是数据部分( .data)的静态数据。使用堆栈可能是必要的，以符合寄存器的惯例。 • 要实现的函数必须使用参数寄存器($a0-$a3)中的值作为输入。汇编文件的数据部分的数据不能直 接用它们的标签来引用。 • 请以可理解的方式设计你的汇编代码，并使用详细的注释来解释你的汇编代码如何工作。 • 提交是通过ISIS进行的。分别上传两个提交文件。 任务1:计算资本化(10分) 任务:实现函数cap_words，该函数返回字符串中大写字母的数量。要实现的函数的C语言签名是。 袠褑袠袠褑 爷 爷 爷 爷 爷 爷 cap_words( char* string)。 $v0 $a0 String是一个指向字符串的第一个字符的指针。这个字符串以空结尾。每个字符的大小是一个字节， 可以用ASCII数字值来检查。例如，在MIPS绿卡上可以找到一个ASCII表。 如果单词的第一个字母是大写字母，那么该单词将被算作大写字母。单词之间总是用空格隔开。不 作为单词的第一个字母出现的大写字母不应计算在内。除了字母之外 Programming Help