程序代写

COMP6991 RSheet Rust 代写

COMP6991 RSheet Rust 代写 这是一份关于计算机科学课程作业的文档,主要内容是使用Rust语言实现一个多用户电子表格程序。 ### 1. 作业概述 – **电子表格介绍** – 电子表格是由单元格组成的网格,每个单元格可以包含一个值,使用“A1”方法寻址。本作业中,电子表格逻辑将使用Rhai语言执行,通过`CellExpr`类型与该语言交互。 – **作业目标** – 获得Rust并发管理经验,设计并构建能正确高效处理并发交互的程序,享受创建应用的过程。 – 明确不考核编写电子表格公式的能力以及编写无用代码的能力。 – **作业提交** – 需提交`mark_request.txt`文件,用于讨论设计的优缺点。 ### 2. 程序运行方式 – **使用起始代码** – 以提供的起始代码为基础,只需实现`rsheet`库,可选择无参数运行查看效果,或使用网络地址接收指令。 – **参考解决方案** – 可使用`6991 rsheet`命令运行参考解决方案检查行为。 ### 3. 评分方式 – **不提供设计卓越评分** – 与作业1不同,此次作业重点在并发设计,而非通用设计。 – **不提供整体反馈** – 原因包括作业1已提供通用Rust反馈、本次重点是并发设计以及期末反馈学生兴趣不大。 – **通过回答问题评分** – 要求回答5个关于设计的问题,反映设计思路,问题需明确具体,可在`mark_request.txt`文件中提问。 ### 4. 任务完成阶段 – **阶段1:基本的获取和设置(15%)** – […]

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CODE 00099F

48024 Programming 2 Assignment 2 OO design, GUIs, MVC, tables, lists Learning Outcomes: This assignment supports objectives 3 – 5 28 October 2024 – 11:59PM (Monday Week 12) Individual Work All work is individual. You must write every line of code yourself except for code copied from study module sample code, lecture sample code, tutor

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EECS20 LC3

Section Title of Ideal Program Screenshot showing the result of running the program introduced in Ch 2 just before halt is executed show both registers final memory location; program counter should be pointing at the halt operation going through Ch 3 will help with this. Section Title of Debug Program 3 screenshots showing the result

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EECS20 Lab 1

Guide to Using LC3Tools Chirag Sakhuja (based on Kathy Buchheit’s guide) The University of Texas at Austin Copyright 2020 © McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior written consent of McGraw-Hill Education. The LC-3 is a piece of hardware, so you might be wondering why we need a simulator. The

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MQF 22:839:571, Financial Modeling I, Spring 2022 Assignment III

Rutgers Business School–Newark & New Brunswick MQF 22:839:571, Financial Modeling I, Spring 2022 Assignment III Assigned: 9/9/22, Due 3/23/22 Download monthly returns observations from CRSP for the SP500 value-weighted average index, the Nasdaq equally-weighted average index, 10 randomly-selected firms and the risk-free rate (3-month T-bill) for the past 10 years (2012.1-2021.12). To make your job

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COMP4161 a2

COMP4161 T3/2024 Advanced Topics in Software Verification Assignment 2 This assignment is released on October 11th, and is due on November 1st 17:59:59. We will accept Isabelle theory (.thy) files only. You are allowed to make late submissions up to five days (120 hours) after the deadline, but at a cost: -5 marks per day.

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CMPEN472 Homework 7

# CMPEN 472 Homework 7 ## 1. 作业目标 – 学习如何使用算术指令、简单的命令行解析以及编写基本的I/O系统子例程。 ## 2. 作业要求 ### 2.1程序功能 – 编写一个程序,在连接到HCS12板的超级终端上实现一个基本的计算器。 ### 2.2输入规则 – 仅输入正的十进制整数。 – 输入和输出的数字最多为四位。 – 有效的运算符为:+,-,*,/。 – 输入带前导零的数字是可以的。 – 仅输入两个数字和它们之间的一个运算符,不允许有空格。 ### 2.3输出规则 – 显示’Ecalc> ‘提示符,并回显用户的按键,直到按下回车键。 – 重复打印用户输入,并在’=’符号后打印答案。 ### 2.4错误处理 – 如果输入格式无效,重复打印用户输入直到错误字符,并在下一行打印错误消息:’Invalid input format’。 – 保持16位内部二进制数格式,检测并标记溢出错误。 – 使用整数除法并截断任何分数。 ### 2.5程序设计 – 程序从$3100开始,数据从$3000开始。 – 要添加大量注释,以便评分者和其他人能够清晰快速地理解程序。 ## 3. 示例输入输出

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COMPSYS705 Exam Test

# COMPSYS705 代写 Exam 代考 ## 1. 考试信息 – **考试日期**:2023年10月17日 – **考试科目**:COMPSYS 705 Formal Methods for Safety Critical Software Test – **总分**:100分 – **权重**:50% – **答题要求** – 回答所有问题,Part I占70分,Part II占30分。 – 问题1 – 4属于Part I,其余属于Part II。 – 展示问题5和6的所有代码。 – 在提供的框内作答,答案应清晰可读。 ## 2. 题目及答题框 ### Q1(20分) 1. **关于进程代数CCS的问题(20 Marks)** – **(a) 进程相似性判断(5 Marks)** – 考虑图1中的两个进程$P, Q$,判断它们是否双相似、弱双相似、相似或无关系,并通过数学方法证明。

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COMP9021 quiz 5

# COMP9021 QUIZ 5 Uses the file cardio_train.csv downloaded from https://www.kaggle.com/sulianova/cardiovascular-disease-dataset Implements a function analyse(gender, age) where gender is one of ‘F (for female) or ‘M’ (for male), and where age is any integer for which we have data in the file (nothing needs to be done if that is not the case). We assume

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COMP9021 quiz 5

Uses the file cardio_train.csv downloaded from https://www.kaggle.com/sulianova/cardiovascular-disease-dataset Implements a function analyse(gender, age) where gender is one of ‘F (for female) or ‘M’ (for male), and where age is any integer for which we have data in the file (nothing needs to be done if that is not the case). We assume that all years have

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