CIT593 HW13 dynamic memory

CIT 593 | Assignment: Dynamic Memory & File I/O | 1
Setting up Codio for this HW:
1) Open the Codio assignment via Coursera
2) From the Codio File-Tree click on: lc4_memory.h and lc4_memory.c
3) Remember to use the Codio “Pre-submission tests” function before submitting the
assignment.
The goal of this HW is for you to write a program that can open and read in a .OBJ file created by PennSim, parse it, and load it into a linked list that will represent the LC4’s program and data memories (similar to what PennSim’s “loader” does). In the last HW, you created a .OBJ file. In this HW, you will be able to read in a .OBJ file and convert it back to the assembly it came from! This is known as reverse assembling (sometimes a disassembler).
RECALL: OBJECT FILE FORMAT
The following is the format for the binary .OBJ files created by PennSim from your .ASM files. It represents the contents of memory (both program and data) for your assembled LC-4 Assembly programs. In a .OBJ file, there are 3 basic sections indicated by 3 header “types” = CODE, DATA, SYMBOL.
● Code: 3-word header (xCADE,

, ), n-word body comprising the instructions. This corresponds to the .CODE directive in assembly.
● Data: 3-word header (xDADA,

, ), n-word body comprising the initial data values. This corresponds to the .DATA directive in assembly.
● Symbol: 3-word header (xC3B7,

, ), n-character body comprising the symbol string. Note, each character in the file is 1 byte, not 2. There is no null terminator. Each symbol is its own section. These are generated when you create labels (such as “END”) in assembly.
LINKED LIST NODE STRUCTURE:
In the file: lc4_memory.h, you’ll see the following structure defined:
The structure is meant to model a row of the LC4’s memory: a 16-bit address, & its 16-bit contents. As you know, an address may also have a label associated with it. You will also recall that PennSim always shows the contents of memory in its “assembly” form. So PennSim reverse-assembles the contents and displays the assembly instruction itself (instead of the binary contents).

CIT 593 | Assignment: Dynamic Memory & File I/O | 2
As part of this assignment, you will read in a .OBJ file and store each instruction in a NODE of the type above. Since they’ll be an unknown # of instructions in the file, you’ll create a linked list of the nodes above to hold all the instructions that are in the .OBJ file.
The details of how to implement all of this will be discussed in the sections of this document that follow.

FLOW CHART: Overview of Program Operation
CIT 593 | Assignment: Dynamic Memory & File I/O | 3

CIT 593 | Assignment: Dynamic Memory & File I/O | 4
IMPLEMENTATION DETAILS:
The first files to view in the helper file are lc4_memory.h and lc4_memory.c. In these files you
will notice the structure that represents a row_of_memory as referenced above (see the section: LINKED_LIST_NODE_STRUCTURE above for the node’s layout). You will also see several helper functions that will serve to manage a linked list of “rows_of_memory” nodes. Your job will be to implement these simple linked list helper functions using your knowledge from the last HW assignment. You must implement everything listed by the comments in the starter code.
Next, you will modify the file called: lc4.c It serves as the “main” for the entire program. The head of the linked list must be stored in main(), you will see in the provided lc4.c file a pointer named: memory will do just that. Main() will then extract the name of the .OBJ file the user has passed in when they ran your program from the argv[] parameter passed in from the user. Upon parsing that, it will call lc4_loader.c’s open_file() and hold a pointer to the open file. It will then call lc4_loader.c’s parse_file() to interpret the .OBJ file the user wishes to have your program process. Lastly it will reverse assemble the file, print the linked list, and finally delete it when the program ends. These functions are described in greater detail below. The order of the function calls and their purpose is shown in comments in the lc4.c file that you will implement as part of this assignment.
Once you have properly implemented lc4.c and have it accept input from the command line, a user should be able to run your program as follows:
./lc4 my_file.obj
Where “my_file.obj” can be replaced with any file name the user desires as long as it is a valid .OBJ file that was created by PennSim. If no file is passed in, your program should generate an error telling the user what went wrong, like this:
error1: usage: ./lc4
There is no need to check that the filename ends in .obj nor should you append .obj to filename passed in without an extension.

CIT 593 | Assignment: Dynamic Memory & File I/O | 5
Problem 1) Implementing the LC4 Loader
Most of the work of your program will take place in the file: called: lc4_loader.c. In this file, you will start by implementing the function: open_file() to take in the name of the file the user of your program has specified on the command line (see lc4_loader.h for the definition of open_file()). If the file exists, the function should return a handle to that open file, otherwise a NULL should be returned.
Also in lc4_loader.c, you will implement a second function: parse_file() that will read in and parse the contents of the open .OBJ file as well as populate the linked_list as it reads the .OBJ file. The format of the .OBJ input file has been in lecture, but its layout has been reprinted above (see section: INPUT_FILE_FORMAT). As shown in the flowchart above, have the function read in the 3-word header from the file. You’ll notice that all of the LC4 .OBJ file headers consist of 3 fields: header type,

, . As you read in the first header in the file, store the address field and the field into local variables. Then determine the type of header you have read in: CODE/DATA/SYMBOL.
If you have read in a CODE header in the .OBJ file, from the file format for a .OBJ file, you’ll recall the body of the CODE section is -words long. As an example, see the hex listed below, this is a sample CODE section, notice the field we should correlate with n=0x000C, or decimal: 12. This indicates that the next 12-words in the .OBJ file are in fact 12 LC-4 instructions. Recall each instruction in LC4 is 1 word long.
CA DE 00 00 00 0C 90 00 D1 40 92 00 94 0A 25 00 0C 0C 66 00 48 01 72 00 10 21 14 BF 0F F8
From the example above, we see that the first LC-4 instruction in the 12-word body is: 9000. (that happens to be a CONST assembly instruction if you convert to binary). Allocate memory for a new node in your linked list to correspond to the first instruction (the section above: LINKED LIST NODE STRUCTURE, declares a structure that will serve as a blue-print for all your linked list nodes called: “row_of_memory”). As it is the first instruction in the body, and the address has been listed as 0000, you would populate the row_of_memory structure as follows.
Code Help
CIT 593 | Assignment: Dynamic Memory & File I/O | 6
In a loop, read in the remaining instructions from the .OBJ file; allocate memory for a corresponding row_of_memory node for each instruction. As you create each row_of_memory add these nodes to your linked list, ordering the list by address (you should use the functions you’ve created in lc4_memory.c to help you with this). For the first 3 instructions listed in the sample above, your linked list would look like this:
The procedure for reading in the DATA sections would be identical to reading in the CODE sections. These would become part of the same linked list, as we remember PROGRAM and DATA are all in one “memory” on the LC-4, they just have different addresses.
For the following SYMBOL header/body:
C3 B7 00 00 00 04 49 4E 49 54
The address field is: 0x0000. The symbol field itself is: 0x0004 bytes long. The next 4 bytes: 49 4E 49 54 are ASCII for: INIT. This means that the label for address: 0000 is INIT. Your program must search the linked list: memory, find the appropriate address that this label is referring to and populate the “label” field for the node. Note: the field: tells us exactly how much memory to malloc() to hold the string, however you must add a byte to hold the NULL. 5 bytes in the case of: INIT. For the example above, the node: 0000 in your linked list, would be updated as follows:
It might be that you come across a label for an address that has not yet been created in your linked list. In this case create a new node and add the label. The other node fields can be left blank. They will be eventually updated. It is possible that an address has two labels in the .OBJ file. In this case make sure to use the last one that occurs.
程序代写 CS代考 加QQ: 749389476
CIT 593 | Assignment: Dynamic Memory & File I/O | 7
Once you have read the entire file; created and added the corresponding nodes to your linked list by address order, close the file and return to main(). If you encounter an error in closing the file, before exiting, print an error, but also free() all the memory associated with the linked list prior to exiting the program.
The feof() function may not work the way you think it should. The eof indicator only returns true AFTER you have attempted to read past the end of the file. If the file position is right at the end of the file but you haven’t tried to read past the end of the file yet, feof() will be false. This means that you need to check all of your calls to fread() or fgetc() to make sure they didn’t hit the end of the file.

CIT 593 | Assignment: Dynamic Memory & File I/O | 8
Problem 2) Implementing the Reverse Assembler
In a new file: lc4_disassembler.c: write a third function (reverse_assemble) that will take as input the populated “memory” linked list (that parse_file() populated) – it will now contain the .OBJ’s contents. reverse_assemble() must translate the hex representation of some of the instructions in the LC4 memory’s linked list into their assembly equivalent. You will need to reference the LC4’s ISA to author this function. To simplify this problem a little, you DO NOT need to translate every single HEX instruction into its assembly equivalent. Only translate instructions with the OPCODE: 0001 (ADD REG, MUL, SUB, DIV, ADD IMM). The immediate value can be formatted with #, x, X, and/or nothing (e.g. ADD R1, R1, #10 == ADD R1, R1, xF == ADD R1, R1, 10).
Data stored at an address in the DATA section should not be translated to an assembly instruction
As shown in the flowchart, this function will call your linked list’s “search_opcode()” helper function. Your search_opcode() function should take as input a 4-bit opcode and return the first node in the linked list that matches the opcode passed in, but also has a NULL assembly field. The opcode that is passed into search_opcode() is a number between 0 and 15 (0x0 and 0xf). The opcode in the instruction is in the leftmost bits of the instruction. For example, here’s the definition of an ADD instruction from the ISA:
0001 ddds ss00 0ttt
but the opcode in the opcode parameter passed to search_opcode() will be:
0000 0000 0000 0001
when looking for an instruction with opcode 1. So you will need to use the C-bitwise operators
to line these two values up before comparing them.
search_opcode() is meant to find the first instruction in the linked list where these two 4-bit fields match. There is an additional constraint that memory rows that already have the assembly instruction (reverse assembled) filled in don’t count as a match.
Said another way, find the first instruction in memory with a matching opcode that hasn’t already been reverse assembled.
When/if a node in your linked list is returned, you’ll need to examine the “contents” field of the node and translate the instruction into its assembly equivalent. Once you have translated the contents filed into its ASCII Assembly equivalent, allocate memory for and store this as string in the “assembly’ field of the node. Repeat this process until all the nodes in the linked list with an OPCODE=0001 have their assembly fields properly translated.
As an example, the figure below shows a node on your list that has been “found” and returned when the search_opcode() function was called. From the contents field, we can see that the HEX code: 128B is 0001 001 010 001 011 in binary. From the ISA, we realize the sub-opcode reveals that this is actually a MULTIPLY instruction. We can then generate the string MUL R1,

CIT 593 | Assignment: Dynamic Memory & File I/O | 9
R2, R3 and store it back in the node in the assembly field. For this work, I strongly encourage you to investigate the switch() statement in C (any good book on C will help you understand how this works and why it is more practical than multiple if/else/else/else statements). I also remind you that you must allocate memory strings before calling strcpy()!

INIT 0000

MUL R1, R2, R3
END 000A
(and so on…)
CIT 593 | Assignment: Dynamic Memory & File I/O | 10
You will find that using C bitwise operators will greatly simplify your implementation. See https://www.tutorialspoint.com/cprogramming/c_bitwise_operators.htm for details.
Problem 3) Putting it all together
As you may have realized, main() should do only 3 things: 1) create and hold the pointer to your memory linked list. 2) Call the parsing function in lc4_loader.c. 3) Call the disassembling function in lc4_dissassembler.c. One last thing to do in main() is to call a function to print the contents of your linked list to the screen. Call the print_list() function In lc4_memory.c; you will need to implement the printing helper function to display the contents of your lc4’s memory list like this:
Notice that

and fields are displayed in hexadecimal with leading zeroes. Please remove all debugging print statements before submitting. Only the memory list should be printed. If the contents of a node are NULL, they should display as 0.
1. You can print (null) for label and assembly instructions when none exist, or leave them blank.
2. There may be very long labels, so that the other entries in that row are pushed to the right. That is fine.
3. You may find the formatting strings “%-20.04x” and “%-20s” useful in keeping your output aligned. This isn’t critical but it is definitely easier to read.
Several things to note: There can be multiple CODE/DATA/SYMBOL sections in one .OBJ file. If there is more than one CODE section in a file, there is no guarantee that they are in order in terms of the address. In the file shown above, the CODE section starting at address 0000, came before the CODE section starting at address: 0010; there is no guarantee that this will always happen, your code must be able to handle that variation. Also, SYMBOL sections can come before CODE sections! What all of this means is that before one creates/allocates memory for a new node in the memory list, one should “search” the list to make certain it does not already exist. If it exists, update it, if not, create it and add it to the list!
Code Help, Add WeChat: cstutorcs
CIT 593 | Assignment: Dynamic Memory & File I/O | 11
Prior to exiting your program, you must properly “free” any memory that you allocated. We will be using a memory checking program known as valgrind to ensure your code properly releases all memory allocated on the heap! Simply run your program: lc4 as follows:
valgrind –-leak-check=full ./lc4 test1.obj
where test1.obj is the name of the .obj file you want to test with.
The following section is in bold and red for a reason. Please make sure you fully understand it!
Valgrind should report 0 errors AND there should be no memory leaks and no accessing uninitialized memory locations prior to submission.
Note: we will run Valgrind on your submission, if it returns errors, you will lose points on this assignment. So watch the VIDEO, learn how to use Valgrind!!
Also note: If your code doesn’t compile or even run, you will lose most of the points of this assignment!
Valgrind will find errors related to accessing uninitialized memory locations. This typically results from assuming that malloc() zeroes out the memory it returns. It does NOT. It can also happen when you access memory locations in an array or string beyond the end of the array or string. While your program may run correctly on your test cases when you have these errors, the results are unpredictable and may cause the test cases run by the autograder to fail.
TESTING YOUR CODE
When writing such a large program, it is a good strategy to “unit test.” This means, as you create a small bit of working code, compile it and create a simple test for it. As an example, once you create your very first function: add_to_list(), write a simple “main()” and test it out. Call it, print out your “test” list, see if this function even works. Run Valgrind on the code, see if it leaks memory or accesses uninitialized memory locations. Once you are certain it works, and doesn’t leak memory, go on to the next function: “search_address()”; implement that, test it out.

CIT 593 | Assignment: Dynamic Memory & File I/O | 12
DO NOT write the entire program, compile it, and then start testing it. You will never resolve all of your errors this way. You need to unit test your program as you go along or it will be impossible to debug.
Remember to use the Codio “Pre-submission tests” function before submitting the assignment.
Where to get input files?
In the last assignment, you created a .OBJ file. Try loading that file into Codio, and use your program on it. You know exactly how that program should disassemble. To test further, bring up PennSim, write a simple program in it, output a .OBJ from PennSim, then read into your program and see if you can disassemble it. You can create a bunch of test cases very easily with PennSim.
You should test your lc4 program on a variety of .OBJ file, not just simple examples. A selection of .OBJ files has been provided in the “obj files for student testing” folder in codio.
Using gdb to debug your program is also HIGHLY recommended.

CIT 593 | Assignment: Dynamic Memory & File I/O | 13
STRUCTURING YOUR CODE:
Preloaded in Codio, you’ll find the files named below that you must implement.
lc4_memory.c
lc4_memory.h
lc4_loader.h
lc4_loader.c
lc4_disasembler.h
lc4_disasembler.c
– must contain your main() function.
– must contain your linked list helper functions.
– must contain the declaration of your row_of_memory
structure & linked list helper functions
– contains your loader function declarations.
– must contain your .OBJ parsing function.
– contains your disassembler function declarations. – must contain your disassembling function.
– must contain the targets:
lc4_memory.o lc4_loader.o lc4_disassembler.o lc4
All, clean and clobber
You cannot alter any of the existing functions in the .h files.
EXTRA CREDIT: A complete reverse assembler:
Finish the disassembler to translate any/all instructions in the ISA. Have your program print the linked list to the screen still, but also create a new output file: .asm. If it works, we should be able to assemble it in PennSim, load the .OBJ file into PennSim and have the memory in PennSim look the same as when we load the test case .OBJ file. Don’t forget to add in the directives (.CODE, .DATA)…the ultimate test of your program will be getting it to assemble using PennSim and produce the same results as the provided .OBJ file.
If you do implement the extra credit, please make sure NOT to output assembly directives for opcodes other than 1 in print_list(). Instead leave the assembly directive column blank or (null) for the other opcodes. The assembly directives for the extra credit opcodes should still appear in the .asm file you generate. Said another way, the output from your program should look like the example above:
0002 9200
0002 9200 CONST R2, 0
● Don’t forget to add directives, labels etc.
● Partial Credit is possible as we will run the program against multiple .obj files. No partial
credit is available for just reverse assembling the instructions and NOT producing a .ASM
file. You MUST produce the .asm file to get any credit.
● The different Registers in assembly instruction should be separate by comma, e.g. ADD
R1, R2, R3

CIT 593 | Assignment: Dynamic Memory & File I/O | 14
● When creating the .asm file, you should change the last 3 characters of the filename (argv[1]) from .obj to .asm.
● The EC is worth 15 points (out of 100) so the highest grade on the assignment is 115%

CIT 593 | Assignment: Dynamic Memory & File I/O | 15
Key Requirements:
o Your code must compile and run, Valgrind should report 0 errors and there should be no memory leaks prior to submission.
o lc4.c and lc4_memory.c
▪ Function requirements explicitly laid out in starter code – implement everything
specified by the comments as these are instructions as well. A copy of the starter
functions is provided below in case of deletion o lc4_loader.c
▪ open_file(): read in a string file_name; if the file exists, open it and return a pointer to the open file, otherwise return NULL
▪ parse_file():
● take in an open file src_file and your linked list memory
● in a loop, read in and parse the ,

, and to determine
the type of header to appropriately allocate room for and populate a new row_of_memory, and add that node to your linked list using the functions in lc4_memory.c, ordering the memory by address
● once entire file is read, and you’ve created and added the corresponding nodes to your linked list in address order, close the file and return to main()
o lc4_disassembler.c
▪ reverse_assemble()
● take in your populated linked list memory
● Find every row_of_memory in your linked list with the OPCODE 0001 (ADD,
MUL, SUB, DIV, ADD IMM), utilizing lc4_memory’s search_opcode() function
● For these nodes, translate the HEX instruction (contents) into its assembly
equivalent and update the assembly field of the node
Important Note on Plagiarism:
o We will scan your HW files for plagiarism using an automatic plagiarism detection tool.
o If you are unaware of the plagiarism policy, make certain to check the syllabus to see the possible repercussions of submitting plagiarized work (or letting someone submit yours).

CIT 593 | Assignment: Dynamic Memory & File I/O | 16
Hints from earlier semesters:
● Checking end of file. Have a look at: https://faq.cprogramming.com/cgi-bin/smartfaq.cgi?id=1043284351&answer=1046476070
● You can assume that the maximum length of an assembly instruction is 100, the maximum length of a label is 100 and the maximum length of a filename is 100.
● Helper Functions are fine. Do not change the headers of the predefined functions and remember to “#include ” in your .h files if your helper functions require definitions from stdio.h
● Do not use externs or global variables.
● The “hexdump -C” command displays an .OBJ file one byte at a time rather than one
word at a time.
● You do not have to check that the addresses in the .OBJ file are valid but feel free to
check if you like
● The order of the steps in the flow chart provide guidance to help you but you can opt for
a different order, as long as your program works.
● There are several possible errors: the input file can’t be found, the input file isn’t validly
formatted, malloc can’t find sufficient memory, etc. It is a best practice to print an error message and exit if any of those things happen but the autograder will not be testing those sort of edge cases.
● While we want your program to have no memory leaks, it is more important that your program actually runs.
● Make sure all of your loops that traverse the memory list look at the first and last element of the memory list. This is a VERY common mistake.
● Q. Do we need to be able to handle OBJ that is both big and small endianness or will it be standardized?
A. You should handle the OBJ files that PennSim produces
● valgrind documentation available at https://www.valgrind.org/docs/manual/quick-start.html#quick-start.interpret
● add_to_list() should keep the memory list in sorted order by address. CODE vs. DATA isn’t relevant.
● Q. Will memory locations in input files only be in user code and data space, or could they be in OS memory?
A. They could be in OS memory as you will see in some of the sample OBJ files provided.
● Q. i am wondering why is the int add_to_list method has a double-pointer of “row_of_memory** head”? Can I delete one of the stars?
A. No, the double pointer is required.
It is because when we add nodes to our linked-list, we want to be able to change the head pointer. Because we pass in a double pointer, we can change what memory (in parse_file) points to, thus allowing us to change the head pointer and add nodes to the beginning of our linked-list. Otherwise, we would just be creating a local copy of the new linked-list non-accessible by main().
● you are allowed to use the standard library of string.h.
● add_to_list – /* check to see if there is already an entry for this address and update the
contents, if so */
This step is asking you to look through memory and see if the address is already
there. If the address is already present in the memory list, replace the

CIT 593 | Assignment: Dynamic Memory & File I/O | 17
“contents” with the new “contents”. The alternative, which doesn’t make sense, would be to create a new entry in the memory list with the same address.
● We will make sure that only files with .obj extensions are passed as arguments to ./lc4
● The x86 (the processor used by Codio) has a different endianness than the LC4. When
doing fread()’s of 2 byte words, swapping occurs to adjust for this. That same swapping doesn’t occur with the fgetc() or fread()’s with size 1.
● Segmentation faults demystified
Segmentation faults are VERY common failures in C programs. They can be hard to pin
First we should understand why they happen.
Segmentation faults are a common class of error in programs written in languages like C that provide low-level memory access. They arise primarily due to errors in use of pointers for memory addressing, particularly illegal access. There are two common cases:
1. trying to dereference a NULL pointer. This often happens when calling a function that returns a pointer or NULL in case of error. If you don’t check the return value from the function and then proceed to dereference the pointer, you will get a segmentation fault.
2. an incorrect assumption that memory on the stack (and heap) is initialized to zero. This is NOT the case. If you want the memory to be initialized to zero, you need to do this explicitly, possibly using the memset() function. You might have code that checks to see if the memory is 0 or NULL and then take some action based on this. If the memory is not initialized to zero, it will have random, unpredictable contents. This is often referred to as (X) or “don’t care” in the lectures.
So, how do you figure out where the segmentation fault is occurring? The simplest way to find out is using gdb. After compiling using the “-g” clang switch and running the program, remembering the procedure for running a program in gdb that takes a command line arguments (the gdb commands “start” and “run” allow you to specify the command line arguments), you will get the segmentation fault. You can then use the gdb “where” command which will tell you the line number in your program where the failure occurs.
For example:
start test1.obj
runs gdb on your lc4 program and starts it with argv[1] set to test1.obj